Skin said:
Dennis, I think one scenario is during the game's first two innings - one for each player. The guy getting 9-8 breaks, makes a ball on the break, and runs 5. The other guy, going to nine, then runs all nine off the table into his hole but scratches on the ninth. So, he spots up that ninth ball and a ball for the foul.
You're saying he has to spot the ninth and the eighth and a ball for the scratch? Doesn't seem right.
Skin
Skin,
Since you quoted post #69 (I like that#), I assume that you read all of it including the post I quoted in it, so I really don't understand how you can then write your post, since it contradicts everything I wrote.
At the risk of being called a repetitive idiot by the Duck I'll say it again. It does not matter a bit how the player going to 8 got 6 balls or when he got them. It does not matter if he made one on the break and then ran five. He has them when his opponent gets to the table and that's all that matters.
The player giving up 9-8 then runs all 9 balls as you say, he scratches as he pockets the 9th ball.
1. He spots up the 9th ball because it was made on a foul shot.
2. Now that he has balls and his inning has ended he puts up the ball for the 9-8.
3. He spots a third ball for scratching on his 9th ball.
That's three balls on the spot.
I'll make (hopefully) my last comment on this question as everybody does not seem to understand that the only way the incoming player can have ball-in-hand(as stated by the OP at the BOTTOM of his post) is if his opponent scratched in a pocket. If there are now two balls on the spot that means they were both shooting for one ball before the scratch. If that's the case, and it is, the incoming player cannot now need two balls since he has not committed any foul. It's not rocket science fellas.
P.S. To anyone contemplating posting a WEI layout: We read the writing at the top of the layout and then look at the layout. If you post additional info at the bottom of the layout many of us will never see it.
Dennis