Scott needs 6, his shot. What should he do?
One rail the 15 while bringing the cube all three rails around for the 13 on the bottom rail.
One rail the 15 while bringing the cube all three rails around for the 13 on the bottom rail.
Make the one and three collide in such a way that they go toward your side and bring the cue back up.
Hit 3ball straight on stick cue ball banking 3 off rail into top of 1 ball might make 13 ball if not you get the 3 and one out.
Eddie, Bingo! In my book you've got a winner. This is definitely the shot I would play from here. You need six and all the balls favor your opponent. In other words, you've got a loser on your hands as it stands right now. Your best bet is the shot you describe and if you are lucky enough to scrape something into your hole from here you can turn defeat into victory so there is very little you have to lose if the shot fails.
You could always get lucky and clear the three and one, maybe even the thirteen and come up with a good safety.
Hell, there is nothing else you can do that won't lead to more trouble than you are in now, so......
I say "You may fire when ready, Gridley!"
Tom
That far away, and CB that close to the rail, I won't hit the 3 very well very often. I'm probably better off rolling on the 1 here and hoping I can frustrate op later.
However, as I look again, there's a good chance of a good result even with a so-so hit. Maybe I will go for the cheese with Gridley's shot.
he hit it bad but it was the right shot.
Brutal spot that Scott was in. The shot he chose was real hard to execute from that distance.. I dont know if I would have chose that but maybe... the only other shot that I see with game winning potential is..... firing the 7/4 into the balls and at the same time with left english caroming the cue ball and try spinning the 13 ball in with the cue ball... Lots of balls moving and you may make one..